Math on amirite? What is this nonsense
In any right angled triangle, the square of the hypotenuse is equal to any other side squared, divided by the squared cosine of the angle formed by that side with the hypotenuse.
WTF!!!? Math on Amirite!!?? This is outrageous and should be removed for disrupting the peace of all the procrastinators here and for making my head hurt trying to understand the post :(
And I came here to get away from school :(
Whoa! How did this get homepaged? It's almost a year old!
oh right!! i totally forgot about that song....
Pythagorean theorem, amirite?
I was just about to say that and I was scrolling down the comments, hoping no one would say it... Then you came along. A squared + b squared = c squared.
Only on a plane. If the triangle is on a curved surface (such as a sphere) it is possible to have a right, equilateral triangle, which would obviously defy the Pythagorean theorem, because a2 + a2 does not equal a2
what is the point in this?
If anyone else had posted this...it would be a statement, not a question.
The hypotenuse of a right angled triangle equals one side time radical 2
That's only in special right triangles to be specific, 45-45-90 triangles.
Let's just all post what we learned in math class today, shall we?
I learned that when your teacher puts a thing of water on your desk not to put your face too close... Even if he says that two hairs are going to fight don't look!
I had to ttake a test and learned that I didn't learn what I was suppossed to. :(
Oh seventh grade Math, how I miss you.
There's a reason I stopped taking math after sophomore year.
Because a2+b2=c2 confused you?
Bad experience with parabolas.