-6 g(n)∈Θ[f(n)]↔∃c1∃c2∃n0: ∀n≥n0,c1f(n)≤g(n)≤c2f(n), amirite?

by Anonymous 10 years ago

I'm sorry, what?

by Anonymous 11 years ago

Gn∈Θ[fn]↔∃c1∃c2∃n0: ∀n≥n0,c1fn≤gn≤c2fn, amirite?

by Anonymous 11 years ago

Genocide interchanges with evil: oxygen is less than or equal to gone which is less than or equal to gas chambers... did I crack the code? or maybe Happy New Years Eve: It'd be nice if we all lived long enough to make it to the next year

by Anonymous 11 years ago

Meh, close enough.

by Anonymous 11 years ago

you gotta tell me what it means I stared at this post longer than I care to admit

by Anonymous 11 years ago

Le sigh. gn is an element of Θ[fn] if and only if there exists c1, c2, and n0 such that for every n≥n0 c1fn≤gn≤c2fn

by Anonymous 11 years ago

thanks for clearing that up wary

by Anonymous 11 years ago

You're welcome :D

by Anonymous 11 years ago

I am really confused by all of this

by Anonymous 11 years ago

See my response to fuzala.

by Anonymous 11 years ago

I still don't follow

by Anonymous 11 years ago